12-03-2015, 04:15 PM
(11-28-2015, 01:47 AM)dipak0mukherjee Wrote: SIR,I am not sure about the solution, but this should be fine:
need hints to solve a sum..
animal cells are growing in a 5 m^3 CSTR with blood serum as feed.feed substrate concentration,S0= 20 KG/M^3,u MAX=0.45 HR^-1,Ks=0.8 kg/m^3,Yx/s=0.8.what feed flow rate is required to achieve 90% conversion of the substratre
So = 20
S = 20 x 0.1 = 2 (90% conversion means 10% residual): i.e steady state concentration of the substrate in chemostat
Umax=0.45 hr-1
Ks = 0.8
V=5
We know, Dilution rate = Flow rate / Volume
And, we also know that Dc (Critical dilution rate) = Umax ( S/ Ks+ S)
So, Dc = 0.45 x 2 / 2.8 = 0.9 / 2.8
So, this should give us flow rate = (0.9/2.8) x 5 = 1.607 m3/hr
(Options might give a better hint towards the right approach).
Best wishes