sir,
i m re posting the questiuon no 51 of 2011...as i have doubt on that..kindly help me to solvbe that one..thank u..question was..
A microorganism grows in a continuous ‘chemostat’ culture of 60 m3 working volume with sucrose as the growth limiting nutrient at dilution rate, D = 0.55 h-1. The steady state biomass concentration is 4.5 Kg dry biomass m-3 and the residual sucrose concentration is 2.0 Kg m-3. The sucrose concentration in the incoming feed medium is 10.0 Kg m-3.
What would be the yield Y X/S (Kg biomass/Kg substrate)?
Possible Answers
Selected Possible Answer
0.562
0.462
0.362
0.162
51)What would be the sucrose concentration in the input feed for the output to be 45 Kg biomass h-I?
Possible Answers
Selected Possible Answer
3.225 Kg m^{-3}
4.425 Kg m^{-3}
5.115 Kg m^{-3}
6.525 Kg m^{-3}...first part ..u helped me...thank u
any one have gate bt 2016 answer key ?
gate bt answer key most probably has not been released officially by iisc..@prankur
LOGGIN IN GOAPS 2016 YOU CAN CHECK YOUR RESPONSES..AND AS FAR I HAVE HEARD THAT IISC WILL PUBLISH ANSWER KEY AFTER DECLARING RESULT...IF YOU ARTE ON FACEBOOK THEN GO FOR THE GROUP BIOTECH LEARNING ACADEMY..THIS GROUP IS UPLOADING QUESTIONS OF GATE 2016 BT ONE BY ONE..
(02-08-2016, 11:46 PM)dipak0mukherjee Wrote: [ -> ]LOGGIN IN GOAPS 2016 YOU CAN CHECK YOUR RESPONSES..AND AS FAR I HAVE HEARD THAT IISC WILL PUBLISH ANSWER KEY AFTER DECLARING RESULT...IF YOU ARTE ON FACEBOOK THEN GO FOR THE GROUP BIOTECH LEARNING ACADEMY..THIS GROUP IS UPLOADING QUESTIONS OF GATE 2016 BT ONE BY ONE..
thanks a lot!
@PRANKUR
MENTI0N NOT.:-) BDW HOW WAS EXAM..I HAVE ALSO APPEARED THIS YEAR
how was gate bt 2016 exam
what will be expected cut off for gate 2016 bt