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For the probability density P(x)=0.5e^-0.5x, the integral...
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(02-15-2017, 04:03 AM)RONIT SHARMA Wrote: [ -> ][Image: 85128236bac056e0027aa644089940b6.jpg]
I guess ans is 0
i think 0.25
find the question below
(02-15-2017, 04:09 AM)prakash choudhary Wrote: [ -> ]i think 0.25
Can you elaborate the approach
Guys, kindly respect the community friendly norms and try to add a couple of lines of the question before adding the snapshot...it will greatly help students in future to find these questions and get assisted....I have edited most of the posted questions to add a couple of lines before the snapshots....it would be great if you could join the cause and try to post a couple of lines of the questions...thanks
One hundred E coli cells are infected by a single lambda phage particle. the ratio of the number of phage particles committing to lysogeny to those committing to lysis is 4:1. Assuming that the average burst size is 80 , the number of free phage particles released after on round of infection is?
(02-15-2017, 04:10 AM)Akshay shinde Wrote: [ -> ]find the question below
I choose option 3
In the summer water consumption is known to decrease overall by 25%. A water board official states that in the summer household consumption decreases by 20%. While the other consumption increases by 70%. Which of the following question is correct?
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(02-15-2017, 06:53 AM)CHANDA7 Wrote: [ -> ]In the summer water consumption is known to decrease overall by 25%. A water board official states that in the summer household consumption decreases by 20%. While the other consumption increases by 70%. Which of the following question is correct?
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There seem errors in official's statement:

Tc = Hc + Oc ---------(1)
(Tc=Total Consumption, Hc= Household consumption, Oc = Other consumption)

In summer:

Consumption decreases by 25%, so new consumption is 0.75 x Tc
Household consumption decreases by 20%, so new Hc is 0.80 x Hc
Other consumption increases by 70%, so new Oc is 1.7 x Oc

i.e 0.75 Tc = 0.80 Hc + 1.7 Oc
From (1), 0.75 ( Hc + Oc) = 0.80 Hc + 1.7 Oc
i.e -0.05Hc = 0.95 Oc
i.e Hc / Oc = - (0.95/0.05)

which turns out -19 and doesn't seem to be fitting with any option.....

(I may be wrong in approaching the question, but this is what first came to mind for solving it...)
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