Aptitude Question: Can be useful for various competitive exams including GATE BT.
A student sent 120 emails in 5 days for getting a PhD position. Each day he/she sent 5 mails more than the previous day. How many emails did he/she send on day 1?
Answer will be shared soon. Till then share your answer and how to approach this problem.
(02-04-2017, 10:01 PM)SunilNagpal Wrote: [ -> ]Aptitude Question: Can be useful for various competitive exams including GATE BT.
A student sent 120 emails in 5 days for getting a PhD position. Each day he/she sent 5 mails more than the previous day. How many emails did he/she send on day 1?
Answer will be shared soon. Till then share your answer and how to approach this problem.
14 emails on first day
14+19+24+29+34=120 emails in five days
Approach? What if someone asks for 12000 mails in 50 days? With the trend of 10 mails more than previous day. It's always good to have a universal approach..
Right answer though! Well done
Let total no.of mails = 't'
Mails sent on first day = 'x'
No.of mails sent more than the previous = 'k'
No.of days, mails were sent ='n'
nth term = 'x+(n-1)k'
Sum of n terms totals down to total no.of mails sent i.e 't'
t = (x)+(x+k)+(x+2k)+(x+3k)+...+(x+(n-1)k)
t = (nx )+ k.n.(n-1)/2
12000 = 50x + 10.50.49/2
12000 = 50x + 12250
50x = 250
x = 5
(02-07-2017, 04:44 PM)Raj Mohan Wrote: [ -> ]Let total no.of mails = 't'
Mails sent on first day = 'x'
No.of mails sent more than the previous = 'k'
No.of days, mails were sent ='n'
nth term = 'x+(n-1)k'
Sum of n terms totals down to total no.of mails sent i.e 't'
t = (x)+(x+k)+(x+2k)+(x+3k)+...+(x+(n-1)k)
t = (nx )+ k.n.(n-1)/2
12000 = 50x + 10.50.49/2
12000 = 50x + 12250
50x = 250
x = 5
Thanks Raj for the structured and universal approach!
(02-07-2017, 04:44 PM)Raj Mohan Wrote: [ -> ]Let total no.of mails = 't'
Mails sent on first day = 'x'
No.of mails sent more than the previous = 'k'
No.of days, mails were sent ='n'
nth term = 'x+(n-1)k'
Sum of n terms totals down to total no.of mails sent i.e 't'
t = (x)+(x+k)+(x+2k)+(x+3k)+...+(x+(n-1)k)
t = (nx )+ k.n.(n-1)/2
12000 = 50x + 10.50.49/2
12000 = 50x + 12250
50x = 250
x = 5
Super approach
Good evening sir,
Sunil sir I want to ask u some suggestion.
Sir I am persuing my MSc.Biotechnology 3 rd sem and I have completed my bachelors in BSc.Agril.Biotechnology(4yrs course).and now I want to go for QA/QC sector in biotechnology, for that could u please guide me how to apply for this or in what way I have to prepare/elligible myself for it.