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GATE BT-2017 Answer Key | Solutions Discussion
(03-20-2017, 11:33 PM)RONIT SHARMA Wrote:
(03-16-2017, 10:58 PM)sadaf188 Wrote: But mere to ek bi marks nai bdhe.....
Ye ques 39 ka answer kaise 0.34 ho gya Hume to smjh nai arha....kisi ko arha h to btaye.
Pehle to 0.15 tha.

Even I got this wrong. Can anyone explain the logic behind this question, how to calculate growth rate from OD?
The equation to use here is U= (ln(N2/N1))÷T2-T1. substitute N for the OD, T for time and U is specific growth rate. Since we are calculating N2/N1 you can directly substitute OD. You will have to calculate the dry cell weight or number of cells only if you need to compare 2 different microbes.
Thanks I got it it, quite simple question: 0.693/2=0.346.

To one of question I wrote 3.89 instead of 3.98 and range started from 3.90. I just lost 2 marks by 0.01 Sad final score "38.06"
Yr mera 39 question ka answer 0.30 aaya hain...will i get mark for it..i made silly mistake in my calculation...its exactly coming o.35
(03-20-2017, 11:33 PM)RONIT SHARMA Wrote:
(03-16-2017, 10:58 PM)sadaf188 Wrote: But mere to ek bi marks nai bdhe.....
Ye ques 39 ka answer kaise 0.34 ho gya Hume to smjh nai arha....kisi ko arha h to btaye.
Pehle to 0.15 tha.

Even I got this wrong. Can anyone explain the logic behind this question, how to calculate growth rate from OD?
We knw tht -dx/dt= ux..we hd to fnd the u=?...though the OD equal to the concn of micro organisim...its mean OD value = x...do the integration...we got ln(x) wid limit 0.3 to 0.6 and time t wid limit 2 to 4
Now , ln( 0.6) - ln (0.3) = u (4-2)
-0.51 - (-1.2) = u×2
0.70 = u ×2
u =0.35 ( answer)
  

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