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GATE BT-2017 Answer Key | Solutions Discussion
This is post no. 101 under the main topic.
(02-15-2017, 04:23 AM)Akshay shinde Wrote: One hundred E coli cells are infected by a single lambda phage particle. the ratio of the number of phage particles committing to lysogeny to those committing to lysis is 4:1. Assuming that the average burst size is 80 , the number of free phage particles released after on round of infection is?

What must Ben the solution for this numerical ? Kindly answer..
 
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This is post no. 102 under the main topic.
(02-15-2017, 04:23 AM)Akshay shinde Wrote: One hundred E coli cells are infected by a single lambda phage particle. the ratio of the number of phage particles committing to lysogeny to those committing to lysis is 4:1. Assuming that the average burst size is 80 , the number of free phage particles released after on round of infection is?

I am sorry if I'm missing some crucial information regarding lytic and lysogenic cycles (which should have been used for approaching this question), I am rather assuming it as a simplistic question....

Given the 4:1 for lysogenic : lytic phages, it is clear than 20 would be lytic phages. 

Now each E.coli will burst once 80 particles have been accumulated. 

So total free particles should be 20x80 = 1600
Sunil Nagpal
MS(Research) Scholar, IIT Delhi (Alumnus)
Advisor for the Biotech Students portal (BiotechStudents.com)
Computational Researcher in BioSciences at a leading MNC


Suggested Reads:
Top Biotech Companies | Top places to work
Indian Biotech Companies and Job Openings
Aiming a PhD in Top Grad School? | These are the Important Points to Consider
Careers in Biotechnology | A list of various Options
Biotechnology Competitive Exams in India
 
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This is post no. 103 under the main topic.
(02-15-2017, 04:40 PM)SunilNagpal Wrote:
(02-15-2017, 04:23 AM)Akshay shinde Wrote: One hundred E coli cells are infected by a single lambda phage particle. the ratio of the number of phage particles committing to lysogeny to those committing to lysis is 4:1. Assuming that the average burst size is 80 , the number of free phage particles released after on round of infection is?

I am sorry if I'm missing some crucial information regarding lytic and lysogenic cycles (which should have been used for approaching this question), I am rather assuming it as a simplistic question....

Given the 4:1 for lysogenic : lytic phages, it is clear than 20 would be lytic phages. 


Now each E.coli will burst once 80 particles have been accumulated. 

So total free particles should be 20x80 = 1600
Thank you sir for the solution . I believe it is a simple numerical as I guess there is no other possible approach for this numerical .
 
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This is post no. 104 under the main topic.
(02-15-2017, 04:00 AM)RONIT SHARMA Wrote:
(02-15-2017, 03:59 AM)Akshay shinde Wrote: Which one of the following graphs represents kinetics of protein precipitation...
"A"

Ohh! I had marked "C" as I was bit confused with those two options.
 
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This is post no. 105 under the main topic.
(02-15-2017, 04:00 AM)RONIT SHARMA Wrote:
(02-15-2017, 03:59 AM)Akshay shinde Wrote: Which one of the following graphs represents kinetics of protein precipitation...
"A"

Sunil sir, what is your opinion on this question ?
 
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This is post no. 106 under the main topic.
Q: Transcription factor X binds a 10bp DNA. X was found to bind at 20 distinct sites, distribution is as following. What is the Consensus sequence pattern.

[Image: 585_217875_0_587434_r_bt_q23.jpg]
 
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This is post no. 107 under the main topic.
(02-15-2017, 07:00 PM)Manoj_Shastry Wrote: Q: Transcription factor X binds a 10bp DNA. X was found to bind at 20 distinct sites, distribution is as following. What is the Consensus sequence pattern.

Option (A) NGTCNNNTNN seems most acceptable consensus (assuming a >=95% confidence).
Sunil Nagpal
MS(Research) Scholar, IIT Delhi (Alumnus)
Advisor for the Biotech Students portal (BiotechStudents.com)
Computational Researcher in BioSciences at a leading MNC


Suggested Reads:
Top Biotech Companies | Top places to work
Indian Biotech Companies and Job Openings
Aiming a PhD in Top Grad School? | These are the Important Points to Consider
Careers in Biotechnology | A list of various Options
Biotechnology Competitive Exams in India
 
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This is post no. 108 under the main topic.
Q: A bacteria has genome of size 6 million bp. If DNA synthesis rate is 1000 bp/ second. How long does it take (in minutes) for replication of genome? 

Q: A proto-oncogene is suspected to have undergone duplication in a certain type of cancer. Which technique can verify gene duplication?

A. Northern blotting
B. Southern blotting
C. South western blotting
D. Western blotting

Q: During anerobic growth, an organism converts Glucose (P) into biomass (Q), Ethanol ®, Acetaldehyde (S) and Glycerol (T). Every mole of carbon in Glucose gets distributed as follows:

1(C-mole P) -> 0.14(C-mole Q) + 0.25(C-mole R) + 0.3(C-mole S) + 0.31(C-mole T) 

From 1800 grams of Glucose fed to organism, amount of Ethanol produced(in grams) is?
 
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This is post no. 109 under the main topic.
A protein expressed in Ecoli under lac promoter and operator. Leaky expression seen in absence of IPTG. 
Which of these methods will minimize leaky expression? 


[Image: 585_217875_0_587434_r_bt_q42.jpg]
 
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This is post no. 110 under the main topic.
Which of the following graph qualitatively represents the growth dynamics?
[Image: b1513aebf5cd2992f27e3be4f431127f.jpg]
 
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