02-07-2017, 08:03 PM
(02-07-2017, 04:44 PM)Raj Mohan Wrote: Let total no.of mails = 't'
Mails sent on first day = 'x'
No.of mails sent more than the previous = 'k'
No.of days, mails were sent ='n'
nth term = 'x+(n-1)k'
Sum of n terms totals down to total no.of mails sent i.e 't'
t = (x)+(x+k)+(x+2k)+(x+3k)+...+(x+(n-1)k)
t = (nx )+ k.n.(n-1)/2
12000 = 50x + 10.50.49/2
12000 = 50x + 12250
50x = 250
x = 5
Thanks Raj for the structured and universal approach!