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Aptitude Question: A student sent 120 emails in 5 days. Each day.... - Printable Version

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Aptitude Question: A student sent 120 emails in 5 days. Each day.... - SunilNagpal - 02-04-2017

Aptitude Question: Can be useful for various competitive exams including GATE BT.

A student sent 120 emails in 5 days for getting a PhD position. Each day he/she sent 5 mails more than the previous day. How many emails did he/she send on day 1?


Answer will be shared soon. Till then share your answer and how to approach this problem.


RE: Aptitude Question: A student sent 120 emails in 5 days. Each day.... - Lavkeshsharma - 02-04-2017

(02-04-2017, 10:01 PM)SunilNagpal Wrote: Aptitude Question: Can be useful for various competitive exams including GATE BT.

A student sent 120 emails in 5 days for getting a PhD position. Each day he/she sent 5 mails more than the previous day. How many emails did he/she send on day 1?


Answer will be shared soon. Till then share your answer and how to approach this problem.
14 emails on first day
14+19+24+29+34=120 emails in five days


RE: Aptitude Question: A student sent 120 emails in 5 days. Each day.... - SunilNagpal - 02-05-2017

Approach? What if someone asks for 12000 mails in 50 days? With the trend of 10 mails more than previous day. It's always good to have a universal approach..
Right answer though! Well done


RE: Aptitude Question: A student sent 120 emails in 5 days. Each day.... - Raj Mohan - 02-07-2017

Let total no.of mails = 't'
Mails sent on first day = 'x'
No.of mails sent more than the previous = 'k'
No.of days, mails were sent ='n'

nth term = 'x+(n-1)k'
Sum of n terms totals down to total no.of mails sent i.e 't'
t = (x)+(x+k)+(x+2k)+(x+3k)+...+(x+(n-1)k)
t = (nx )+ k.n.(n-1)/2

12000 = 50x + 10.50.49/2
12000 = 50x + 12250
50x = 250
x = 5


RE: Aptitude Question: A student sent 120 emails in 5 days. Each day.... - SunilNagpal - 02-07-2017

(02-07-2017, 04:44 PM)Raj Mohan Wrote: Let total no.of mails =  't'
Mails sent on first day  = 'x'
No.of mails sent more than the previous = 'k'
No.of days, mails were sent  ='n'

nth term = 'x+(n-1)k'
Sum of n terms  totals down to total no.of mails sent i.e 't'
t = (x)+(x+k)+(x+2k)+(x+3k)+...+(x+(n-1)k)
t = (nx )+ k.n.(n-1)/2

12000 = 50x + 10.50.49/2
12000 = 50x + 12250
    50x = 250
        x = 5

Thanks Raj for the structured and universal approach!


RE: Aptitude Question: A student sent 120 emails in 5 days. Each day.... - Roshan Raj - 05-16-2017

(02-07-2017, 04:44 PM)Raj Mohan Wrote: Let total no.of mails = 't'
Mails sent on first day = 'x'
No.of mails sent more than the previous = 'k'
No.of days, mails were sent ='n'

nth term = 'x+(n-1)k'
Sum of n terms totals down to total no.of mails sent i.e 't'
t = (x)+(x+k)+(x+2k)+(x+3k)+...+(x+(n-1)k)
t = (nx )+ k.n.(n-1)/2

12000 = 50x + 10.50.49/2
12000 = 50x + 12250
50x = 250
x = 5

Super approach


RE: Aptitude Question: A student sent 120 emails in 5 days. Each day.... - vaishnavi dudhe - 06-07-2017

Good evening sir,
Sunil sir I want to ask u some suggestion.
Sir I am persuing my MSc.Biotechnology 3 rd sem and I have completed my bachelors in BSc.Agril.Biotechnology(4yrs course).and now I want to go for QA/QC sector in biotechnology, for that could u please guide me how to apply for this or in what way I have to prepare/elligible myself for it.